USING
(x + a)(x + b) = {x}^{2} + (a + b)x +ab(x+a)(x+b)=x
2
+(a+b)x+ab
FIND
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Answered by
5
(i)
103 * 104
=> (100 + 3) * (100 + 4)
=> (100)² + (3 + 4) * 100 + (3)(4)
=> 10000 + 700 + 12
=> 10712
(ii)
5.1 * 5.2
=> (5 + 0.1)(5 + 0.2)
=> (5.1)² + (0.1 + 0.2) * 5 + (0.1)(0.2)
=> 25 + 1.5 + 0.02
=> 26.52
(iii)
103 * 98
=> (100 + 3)(100 - 2)
=> (100)² + (3 - 2) * 100 + (3)(-2)
=> 10000 + 100 - 6
=> 10094
(iv)
9.7 * 9.8
=> (9 + 0.7)(9 + 0.8)
=> (9)² + (0.7 + 0.8) * (9) + (0.7)(0.8)
=> 81 + 13.5 + 0.56
=> 95.06
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Answered by
4
HERE IS YOUR ANSWER
1. 103+104
=(100+3)(100+4)
=100^2 + (3+4)100 + (3×4)
= 1000+700+12
= 10712
2. 5.1×5.2
=(5+0.1)(5+0.2)
=5^2 + (0.1+0.2)5 + (0.1×0.2)
= 25+1.5+0.02
= 26.52
3. 103×98
=(100+3)(100-2)
= 100^2 + (3-2)100 + (3×-2)
= 1000+100-6
= 10094
4. 9.7×9.8
=(9+0.7)(9+0.8)
= 9^2 + (0.7+0.8)9 + (0.7×0.8)
= 81+13.5+0.56
= 95.06
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