Math, asked by wkaktatksgzgostisk, 2 months ago

Using (x + a) (x + b) = x² + (a + b) x + ab, find 601 * 602 .​

Answers

Answered by aniketaryan960
0

Step-by-step explanation:

= 601 x 602

= (600 + 1) (600 + 2)

= (600)² + (1 + 2)600 + 1*2

= 360000 + 1800 + 2

= 361802

Answered by akn0102
0

Answer:

required answer is 361802

Step-by-step explanation:

Given ,  (x + a) (x + b) = x² + (a + b) x + ab

now ,

we can write,  601 = 600+1 and 602=600+2

taking x = 600 , a = 1 , b = 2

Then 601 × 602 = (600+1) (600+2)

= (x + a) (x + b)    ; { since x = 600 , a = 1 , b = 2 }

= x² + (a + b) x + ab [from given condition]

= (600)^2 + (1+2)×600 + 1×2

= 360000 + 3×600 + 2

= 360000 + 1800 + 2

= 361802

hence the following answer of 601×602 is 361802

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