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F = ma
where, m= 2 kg and a = 4 m/s^2
therefore, F = 2 ×4 = 8 N
So, spring constant; k = F/∆x
where, ∆x = 20 cm = 0.2 m
So, k= 8÷0.2
= 40 N /m
where, m= 2 kg and a = 4 m/s^2
therefore, F = 2 ×4 = 8 N
So, spring constant; k = F/∆x
where, ∆x = 20 cm = 0.2 m
So, k= 8÷0.2
= 40 N /m
TheGod:
how 80 N /m ....maybe answer is wrong
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