Question

उदाहरण 10.2
कोई 4.0 cm साइज़ का बिंब किसी 15.0 cm फोकस
दूरी के अवतल दर्पण से 25.0 cm दूरी पर रखा है। दर्पण से
कितनी दूरी पर किसी परदे को रखा जाए कि स्पष्ट प्रतिबिंब
प्राप्त हो? प्रतिबिंब की प्रकृति तथा साइज़ ज्ञात कीजिए।​

Answer 1

Answer:

give- h=4cm

u= -25

f= -15

formula; 1/v - 1/u =1/f

put the values

1/v - 1/ - 25 = 1/-15

on solving

v = - 75/2

= - 32.5

hight of image

formula;

h'/h = - v/u

= - ( - 32.5/-25)× 4

= - 10 cm

hence height of image is 10 cm

- sign shows image is inverted

Answer 2

Answer:

hi yaad kar liye sara to get a chance for her and gave me a

Explanation:

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