English, asked by indiankhiladi, 2 months ago

utube Channel brainly wala for multiple answers b​

Answers

Answered by HearthackerAshu15
6

Explanation:

\huge\mathcal{\fcolorbox{lime}{black}{\blue{ŋɿƈɛ \: զųɛʂཞıơŋ}}}

 \huge\star\underline{\mathtt\orange{❥ǫ} \mathfrak\blue{ᴜ }\mathfrak\blue{ᵉ} \mathbb\purple{ Տ}\mathtt\orange{ㄒ} \mathbb\pink{ɨօຖ}}\star\:

☆What is life

\huge{\mathcal {\purple {ƛ}\green {ຖ}\pink {ֆ}\blue {ώ}\purple{ɛ}\green {ʀ}}}

☆Life is a characteristic that distinguishes physical entities that have biological processes, such as signaling and self-sustaining processes, from those that do not, either because such functions have ceased, or because they never had such functions and are classified as inanimate.

\huge\boxed{\fcolorbox{black}{red}{Brainlist please✔}}

\huge\blue{Hope\: it\: helps}

\huge\colorbox{orange}{ƛşнƲ࿐ ❤}

 {\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@HearthackerAshu15}}}}}}}}}}}}}}}

Answered by MrsHangover
3

 \huge \bf  \underline\red{Answer : }

We know that according to Ohm’s law

V = IR

where

V= potential difference

I= Current

R = Resistance

We can also modify the equation as

I=V/R ——- (i)

Now given that the potential difference across the two ends of the component decreases to half

∴ So let the new potential difference be Vʹ=V/2

Resistance remains constant across the electrical component

So the new current is drawn through the electrical component is Iʹ = Vʹ/R

= (V/2)/R {Substituting Vʹ=V/2 in the above equation}

= (1/2) (V/R)

= (1/2) I = I/2

Therefore, the amount of current flowing through the electrical component is reduced by half.

 \color{lime} \boxed{thank \: uhh : )}

Similar questions