UTUN
JU UI IUIT UMU Melluny de 1.o 10° Rg mand 13.6 x 100 kg m respectively] (Ans. 0.574]
Some lead shots were put in a flat bottomed test tube and the combination, when weighed in air, was
found to weigh 22.65 g. It was found to float in water with 5.66 g of its length immersed under water. The
corresponding immersed length of the same test tube, in kerosene, was found to be 6.8 cm. Use this
information to find (a) the area of cross section of the tube (b) the mass of water displaced by floating test
tube and (c) the relative density of kerosene.
[Ans.(a) 4 cm2 (b) 22.64 g (c) 0.832]
Answers
Answered by
0
Answer:
22.64g is the answers so you write this one only
Similar questions