Question

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Consider the following complex
Co (NH) CO] CO,
The coordination number, oxidation number,number
of d-electrons and number of unpaired d-electrons on
the metal are, respectively
a) 6,3, 6, 0
b) 7,2, 7,1
c) 7, 1, 6, 4
d) 6, 2, 7,3
number​

Answer 1

6, 3, 6, 0

7, 2, 7, 1

7, 1, 6, 4

6, 2, 7, 3

Answer :

A

Solution :

<br> C.N. of Co = 6 , O.S. of

<br> It contain

as the centrl metal ion <br> Co(Z = 27 ) :

<br>

<br> No. of d-electrons in metal ion = 6 <br>

and

being strogands will forcr the six 3d-electrons to pair up in three d-orbital . This is followed up

- hybridisation to give octahedral complex. The complex have no unpaired electron.