Question

UUSES.
A convex lens of focal length 15 cm is placed at the origin with its optical axis coinciding with the x-axis. A ray of light given by y
=-*+ 1 is incident on the lens. The equation of refracted ray is y = -0.1 mx + C. (x and y are in cm). Find the value of m.
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Answer 1

Answer:

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Answer 2

The given question is not complete. Refer to the question given below:

A convex lens of focal length 15 cm is placed at the origin with its optical axis coinciding with the x-axis. A ray of light given by y = -x/3 + 1 is incident on the lens. The equation of refracted ray is y = -0.1 mx + C. (x and y are in cm). Find the value of m.

Concept:

The formula for the focal length of the mirror is given as- 1/v - 1/u = 1/f

Given:

Focal length = 15cm

Equation of refracted ray y = - 0.1 mx + c

Ray of light is given by the formula, y = - x/3 + 1

Find:

We need to determine the value of m for the given convex lens.

Solution:

For y = 0, value of x becomes - 3

For x = 0, y becomes 1

We have the focal length formula as-

1/v - 1/u = 1/f

1/x - 1/3 = 1/15

Therefore, x = 5/2

1/y + 1 = 1/15

Therefore, 1/y = 1/15 - 1 = 1 - 15/15 = -14/15 = -15/14

Putting value in

Equation of refracted rays is given as

15/14 = - 0.1 m (5/2) + 1

15/14 - 1 = - 0.1 m

1/14 = -0.1 m (5/2)

1/14 * 2/5

2/70 = 0.28

m = 0.28

Thus, the value of m becomes 0.28.

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