Question

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1. Baichung's father is 26 years younger than Baichung's grandfather and 29 years
older than Baichung. The sum of the ages of all the three is 135 years. What is the
age of each one of them?
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Answer 1

Answer:

Let x be Baichung's age.

Then,

Baichung's father age = x + 29

Baichung's grandfather's age = (x + 29)+ 26

Their total sum= 135

Now ,

By question , we have

x + x + 29 + x + 29+26 = 135

=> 3x + 84= 135

=> 3x = 135 - 84

=> x = 54/3

=> x = 18

Thus ,

Baichung's age = 18

his father's age = 18+29= 37

his grandfather's age = 18+29+26=63

Answer 2

Answer:

Given :

Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .

The sum of the age of all the three is 135 years.

Solution :

$\longmapsto\tt{Let\:Age\:of\:Grandfather\:be=x}$

As Given that Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .So ,

$\longmapsto\tt{Age\:of\:Baichung's\:Father=x-26}$

$\longmapsto\tt{Age\:of\:Baichung=x-26-29=x-55}$

A.T.Q :

$\longmapsto\tt{x+x-26+x-55=135}$

$\longmapsto\tt{3x-81=135}$

$\longmapsto\tt{3x=135+81}$

$\longmapsto\tt{3x=216}$

$\longmapsto\tt{x=\cancel\dfrac{216}{3}}$

$\longmapsto\tt\bf{x=72}$

Value of x is 72 .

Therefore :

$\longmapsto\tt{Age\:of\:his\:Grandfather=x}$

$\longmapsto\tt\bf{72\:yrs}$

$\longmapsto\tt{Age\:of\:his\:Father=72-26}$

$\longmapsto\tt\bf{46\:yrs}$

$\longmapsto\tt{Age\:of\:Baichung=72-55}$

$\longmapsto\tt\bf{17\:yrs}$