uv light of wavelength 800 A and 700A were allowed to fall pn hydrogen atom in their ground state is found to liberate electron with kinetic energy 1.8 ev and 4 ev respectively calculate value of plank constant.
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λ
hc
=KE+WorkFunction
λ
1
hc
=KE
1
+WorkFunction→1
λ
2
hc
=KE
2
+WorkFunction→2
hc[
λ
2
1
−
λ
1
1
]=KE
2
−KE
1
hc[
700
1
−
800
1
]=4−1.8
5600
hc
=2.2
⇒hc=2.2×1.6×10
−19
×5600×10
−10
Jm
⇒h=
3×10
8
ms
−1
2.2×1.6×10
−19
×5600×10
−10
Jm
⇒h=6.57×10
−34
Js
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