Question

Uz factorise (i) x³-4x²-7x+10=0​

Answer 1

Answer:

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Step by step explanation :-

x^3-4x^2-7x+10

let x=1

(1)^3-4(1)^2-7(1)+10

1-4-7+10=0

so, (x- 1) is a factor

now divide x^3-4x^2-7x-10 from (x - 1) =x^2-3x-10

then by splitting the middle term

= x^2-3x-10

= x^2-5x+2x-10

= x(x– 5)+2(x- 5)

= (x+2)(x- 5)

factors are (x- 1)(x+2)(x- 5)