V= 120 cm
O Two concave mirror each of R=40 cm are placed
such that their principal axis
are porallel to each
1 cm. Both are at a separation of
Consider the first reflection of Mi. Taking
the location of object as
of object as origin. Find the
coordinates of image
other
by
100 cm. Consider the
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Explanation:
Using mirror formula for first reflection:
(1/f) = (1/v) + (1/u)
⇒ (1/-20) = (1/v) + (1/-70) ⇒ (1/v) = (1/60) –(1/20)
⇒ v = -30 cm Using mirror formula for first reflection:
(1/f) = (1/v) + (1/u) ⇒ (1/-20) = (1/v) + (1/-70) (1/v) = (1/70) – (1/20) = [(2-7)/140] ⇒ v = -(140/5) = -28 cm
Height of I2 ⇒ m = (-30/-60) = I2/-1 ⇒ I1 = (1/2) cm
Height of first image from x-axis = 1 + (1/2) = 3/2 cm
Height of I2 ⇒ m = (-28/-70) = 2I2/3 ⇒ I2 = [3*28]/[2*70] I2= -0.6 cm co-ordinate of I2= (12 - 0.6)
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