Question

V
14. A particle moves in a circle of radius 5 cm with
constant speed and time period 0.2 pie s. The
acceleration of the particle is

Answer 1

Answer:

The acceleration of the particle is 5 m/s²

Explanation:

Radius of the circular path R = 5 cm = 0.05 m

Time period T = 0.2π seconds

Therefore,

Angular velocity ω = 2π/T = 2π/0.2π = 10 rad/sec

Therefore, linear velocity of the particle v = Rω = 0.05 × 10 m/s

                                                                               = 0.5 m/s

Acceleration of the particle a = v²/R

                                                = 0.5²/0.05 = 0.25/0.05 m/s²

                                                                   = 5 m/s²

Therefore, the acceleration of the particle is 5 m/s²

Hope this helps.