Question

v=141.4sin(314t+10°) i=14.14sin(314t-20°) To find 1) the power factor 2)the power delivered to the circuit 3) draw the phasor diagram​

Answer 1

Explanation:

v(t) = 141.4 sin (314 t + 10°) This expression indicates a sinusoidally varying alternating voltage at a frequency ω = 314 rad/sec, f = 50Hz V = RMS voltage (Peak voltage)/√2 = 100volts The expression for the current gives the following data : I = RMS value = 14.14/√2 = 10 amp frequency = 50 Hz, naturally. Phase shift between I and V = 30°, I lags behind V. (i) Power factor of the circuit = cos 30° = 0.866 lag (ii) P = VI cos φ = 100 × 10 × 0.866 = 866 watts (iii) Phasor diagram as drawn below, in Fig..Read more on Sarthaks.com - https://www.sarthaks.com/493062/a-voltage-v-t-141-4-sin-314-t-10-is-applied-to-a-circuit-and-the-steady-current-given-by