Question

V 2
Problems on Equation of a line
7. The equation of the line passing through the point (2, -3) and parallel to the line joining the points
(1, 2) and (-1, 5) is
1) 3x + 2y = 0
2)
3y + 12 = 0​

Answer 1

Answer:

1) 3x+2y=0

Step-by-step explanation:

we know that

Y=mx+c is eqn of straight line

first we find slope from parallel line

m = 5-2/-1-1

m= -3/2

value of m put in straight line eqn

Y =-3/2x+c

if the point (2, -3) lies on Y=-3/2x+c line then these point satisfied the eqn means put the value of x and y in eqn so we get value of C

-3 = -3/2×2+c

C=0

then resultant eqn is

Y=-3/2x

2Y=-3x

2y+3x=0