Question

v^2-u^2=2as
check its correctness
where ,
v=final velocity
u=initial velocity
a=acceleration
s=displacement​

Answer 1

area below the graph line area of trapezium equal to one by two u + v multiply time putting the value of time equal to to V minus u by acceleration transposing 2 acceleration on left side it became 2as = v^2 - u^2