Question

v^2 - u^2 = 2as how it is

Answer 1

$use \: \: the \: \: differential$

Explanation:

$we \: \: know \: \: \boxed{a = \frac{dv}{dt} } \\ Now, \: \: \: \: \: \: a = \frac{dx}{dt} \times \frac{dv}{dx} \\ \: \: \: \: \: \: \: \: a = v \frac{dv}{dx} \\ \: \: \: vdv = adx \\ \: \: \: \int_{u}^{v}vdv = a \int _{0}^{s} dx \\ [ \frac{ {v}^{2} }{2} ] _{u}^{v} = a[x]_{0}^{s} \\ \: \: \: \: \: \: \: \: \: \: \: \frac{ {v}^{2} - {u}^{2} }{2} = a(s - 0) = as \\ {v}^{2} - {u}^{2} = 2as$