v=2t-4 then what is distance covered in first 3 seconds
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Explanation:
GIVEN VELOCITY IN TERMS OF TIME .
V = 2T -4
DIFFERENTIATING WITH RESPECT TO TIME WE GET DISPLACEMENT IN TERMS OF TIME.
∫V = ∫(2T-4)
S = 2T²/2-4T
S = T²-4T
DIASTANCE COVERED IN 3 SECONDS ,
S = 3²-4*3
S = 9-12
S = -3 M
THAT MEANS THE DISPLACEMENT OF THE BODY IS 3 M IN OPPOSITE DIRECTION OF INITIAL DIRECTION OF MOTION OF THE BODY.
HOPE THIS HELPS.
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