Physics, asked by krishnaditya104, 11 months ago

v=2t-4 then what is distance covered in first 3 seconds

Answers

Answered by raj3294
0

Answer:

Explanation:

GIVEN VELOCITY IN TERMS OF TIME .

V = 2T -4

DIFFERENTIATING WITH RESPECT TO TIME WE GET DISPLACEMENT IN TERMS OF TIME.

∫V = ∫(2T-4)

S = 2T²/2-4T

S = T²-4T

DIASTANCE COVERED IN 3 SECONDS ,

S = 3²-4*3

S = 9-12

S = -3 M

THAT MEANS THE DISPLACEMENT OF THE BODY IS  3 M IN OPPOSITE DIRECTION OF INITIAL DIRECTION OF  MOTION OF THE BODY.

HOPE THIS HELPS.

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