Question

v=2t. Find speed at 3sec. If at t=0 body is 2m behind origin. ​

Answer 1

V= 2t ,given

So at t= 3 , you will have v= 2 x 3 = 6m/s

Now it is given that it is 2m behind the origin at t=0

And we know v=u+at

So if u= 0

We will have v= at

And that is the format in which we have been given the value of v

So a = 2

Now for distance , you have s= ut+ 1/2 at^2

And u=0

So s= 1/2 a t^2


And t=3 ,given


So s = 1/2 x 2 x 9


= 9m

And 2m is behind origin

So it will be 7m ahead of origin


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