Question

V= 2t² - 4t find acceleration at t = 3 secons.​

Answer 1

Answer:

v = 2t² - 4t

Now, dv/dt = a

So, dv/dt = 4t - 4

a = 4t - 4

Now, t = 3s

So, a = 4(3) - 4

a = 12 - 4

a = 8m/s²

Hope it helps you!!

Answer 2

Answer:

Given,

$v = 2 {t}^{2} - 4t$

We have,

$a = \frac{dv}{dt}$

So,

$a(t) = \frac{d(2 {t}^{2} - 4t) }{dt} = 4t - 4$

Hence,

$a(3) = 8m {s}^{ - 2}$