(v) (2x - 1)(x – 3) = (x + 5)(x - 1)
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Step-by-step explanation:
(2x - 1)(x – 3) = (x + 5)(x - 1)
=> 2x(x-3)-1(x-3)=x(x-1)+5(x-1)
=> 2x^2 - 6x - x+3 = x^2 - x + 5x -5
=> 2x^2 - x^2 - 6x -x +x -5x +3 +5 =0
=> x^2 -11x +3+5=0
=> x^2 - 11x + 8 =0
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