(v) 2x + 3y+4=0; x-5y = 11
(vi)
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2x+3y=-4 ......... equation first
x-5y=11............ equation second
multiplied equation second by 2 and subtract from equation first
2x+3y=-4
-2x+10y=-22
13y=-26
y=-26/13
y=-2
now, putting the value of y in equestion first
2x+3×-2=-4
2x-6=-4
2x=-4+6
x=2/2
x=1
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