v) 3p²q +5pq² + 2 par
Answers
Answered by
0
Answer:
i+3j−2k,2i−j+4k and 3i+2j+pk are coplanar
⇒
1
2
3
−1
2
−2
4
p
=0
⇒(−p−8)−3(2p−12)−14=−7p+14=0
∴p=2
Hence, option B.
Answered by
0
Answer:
plz send the correct question
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