Question

v=3t2-4t
find acceleration at t=4 sec​

Answer 1

Explanation:

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Answer 2

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$v \: = 3 {t}^{2} - 4t$

So

Acceleration

$= \frac{dv}{dt} = 6t \: - 4$

So the required Acceleration is

$= 6 \times 4 - 4 = 20 \: \: unit$

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