V=3x+4y. Find F=? on q=2C
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7
Answer:
10 N
Explanation:
Given :
V ( x , y ) = 3 x + 4 y
We know :
E = - d V / d r
Partially differentiating we get :
E_x = 3
E_y = 4
Now net electric field :
E_net = √ ( 3² + 4² )
E_net = 5 N C⁻¹
We are asked to find Force :
We know :
F = q E_net
F = 5 × 2 N
= > F = 10 N
Therefore , force on 2 C is 10 N.
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