Question

(v) 4a2 + 2ab + b2 and 2 a - b (multiply)
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Answer 1

Step-by-step explanation:

$(4 {a}^{2} + 2ab + {b}^{2})(2a - b)$

$2a(4 {a}^{2} + 2ab + {b}^{2}) - b(4 {a}^{2} + 2ab + {b}^{2})$

$8 {a}^{(1 + 2)} + 4 {a}^{(1 + 1)}b + 2a {b}^{2} - 4 {a}^{2}b - 2a {b}^{( 1 + 1)} - {b}^{(1 + 2)}$

$8 {a}^{3} + 4 {a}^{2}b + 2a {b}^{2} - 4 {a}^{2}b - 2a {b}^{2} - {b}^{3}$

$8 {a}^{3} - {b}^{3}$