Math, asked by purneetkaur424, 11 months ago

(v) 4x(x + y - z), 3yx-y-z). - 2y x-y-2)
5. Subtract:
() 3pq(p - g) from 2pq(p+q)
(ii) - 3y(4y + 3x) from 2x(x2 - y)
(iii) 5(x - 2) from 4(-3)
(iv) 22 (z - x - y) from 2yaz-y-x)
(v) 4x (3x - 4y - 52) from 73(2x - 8y - 72)
Simplify:
(i) 4c(-a + b + c) - 3ala + b + c)
+ 2bla-b+

Answers

Answered by devishri1977
3

Answer:

Step-by-step explanation:

1)2pq(p+q) - 3pq(p-q) = 2p²q+2pq² - 3p²q + 3pq²  = 5pq² - 3p²q

2) 2x(x²-y) - { -3y(4y+3x) } = 2x³-2xy + 3y(4y+3x) = 2x³- 2xy  + 12y²+ 9xy

= 2x³ + 7xy  + 12y²

3)4(-3) - 5(x-2) = -12 - 5x +10 = -2 -5x

4)2yaz - y - x - 22(z-x-y) = 2yaz - y - x - 22z + 22x + 22y

= 2yaz + 21y + 21x  -22z

5)73(2x - 8y - 72) -  4x (3x - 4y - 52)

= 146x - 584y - 5246 - 12x² + 16xy + 208x

= 354x -584y -5246 - 12x² + 16xy

6)) 4c(-a + b + c) - 3a(a + b + c) + 2b(a-b+ c)

= -4ac + 4bc + 4c² - 3a² -3ab -3ac + 2ab -2b² +2bc

​= -7ac + 6bc + 4c² - 3a² - ab - 2b²

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