Question

v) 4x2 -4ax + (a2 - b2) = 0​

Answer 1

$x = \frac{ - ( - 4a) ± \sqrt{ {( - 4a)}^{2} - 4(4)( {a}^{2} - {b}^{2}) } }{2(4)} \\ x = \frac{4a ± \sqrt{16 {a}^{2} - 16 {a}^{2} + 16 {b}^{2} } }{8} \\ x = \frac{4a ± \sqrt{16 {b}^{2} } }{8} \\ x = \frac{4a ± 4b}{8} = \frac{a ± b}{2}$