Question

V)
5
D
3
B
.
E 6.4-X C
In the figure, A-D-C and B-E-C. seg DE || side AB. If AD=5, DC = 3,
BC = 6.4, then find BE and EC.​

Answer 1

Answer:

your question is incomplet

Answer 2

Answer:

In ∆ABC, seg DE || side AB [Given] ∴ DC/AD = EC/BE [Basic proportionality theorem] ∴ 3/4 = (6.4 - x)x ∴ 3x = 5 (6.4 – x) ∴ 3x = 32 – 5x ∴ 8x = 32 ∴ x = 32/8 = 4 ∴ BE = 4 unitsRead more on Sarthaks.com - https://www.sarthaks.com/850416/in-the-adjoining-figure-a-d-c-and-b-e-c-seg-de-side-ab-if-ad-5-dc-3-bc-6-4-then-find-be?show=850419#a850419