(V)
5log10 (2) + 2 log10 (3) - 6log64 (4)
Please answer with Explanation
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Answered by
0
Answer is 0.6592 ......
study9095:
Answer should be in log format..
Answered by
4
Logarithm,
We have,
![5 log_{10}(2) + 2 log_{10}(3) - 6log_{64}(4) \\ log_{10}( {2}^{5} ) + log_{10}( {3}^{2} ) - 6 log_{ {2}^{6} }( {2}^{2} ) \\ log_{10}(32 \times 9) - 2 log_{2}(2) \\ log_{10}(288) - 2 \: \: \: \: \: \: \: \: \: \: (as \: log_{x}(x) = 1) \\ or \: 0.4594 5 log_{10}(2) + 2 log_{10}(3) - 6log_{64}(4) \\ log_{10}( {2}^{5} ) + log_{10}( {3}^{2} ) - 6 log_{ {2}^{6} }( {2}^{2} ) \\ log_{10}(32 \times 9) - 2 log_{2}(2) \\ log_{10}(288) - 2 \: \: \: \: \: \: \: \: \: \: (as \: log_{x}(x) = 1) \\ or \: 0.4594](https://tex.z-dn.net/?f=5+log_%7B10%7D%282%29+%2B+2+log_%7B10%7D%283%29+-+6log_%7B64%7D%284%29+%5C%5C+log_%7B10%7D%28+%7B2%7D%5E%7B5%7D+%29+%2B+log_%7B10%7D%28+%7B3%7D%5E%7B2%7D+%29+-+6+log_%7B+%7B2%7D%5E%7B6%7D+%7D%28+%7B2%7D%5E%7B2%7D+%29+%5C%5C+log_%7B10%7D%2832+%5Ctimes+9%29+-+2+log_%7B2%7D%282%29+%5C%5C+log_%7B10%7D%28288%29+-+2+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%28as+%5C%3A+log_%7Bx%7D%28x%29+%3D+1%29+%5C%5C+or+%5C%3A+0.4594)
That's it
Hope it helped (^_^メ)
We have,
That's it
Hope it helped (^_^メ)
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