Question

(v) 6abc, 24a²b, 12ab2​

Answer 1

Answer:

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Answer 2

Answer:

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6abc, 24ab2, 12a2b

= (2 × 3 × a × b × c), (2 × 2 × 2 × 3 × a × b × b) and (2 × 2 × 3 × a × a × b)

Common factors are 2 × 3 × a × b = 6ab

Hence, the common factor = 6ab

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