Question

V=(6x-8xy-8y+6yz) volt. Find force on charge 2C placed at (1,1,1).[Ans:-4 root 35)N​

Answer 1

Answer:

4 √ 35 N

Explanation:

Given :

V = ( 6 x - 8 x y + 8 y + 6 y z )

We know :

E = - d V / d r

Now partially differentiating we get :

E_x = 6 - 8 y

E_y = - 8 x - 8 + 6 z

E_z = 6 y

Now at ( 1 , 1 , 1 )

E_x = - 2

E_y = - 10

E_z = 6

Now net electric field :

E_net = √ ( ( - 2 )² + ( - 10 )² + ( 6 )² )

E_net = √ ( 4 + 100 + 36 )

E_net = √ 140 N C⁻¹

We are asked to find force :

We have change q = 2 C

We know :

F = q E

Putting values here we get :

F = 2 × √ 140 N

= > F = 4 √ 35 N

Hence we get required answer!