V A piece of wire of resistance 200 s drawn out so that sleg is increased
Calculate the resistance of the wire in the new situation
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Answer:
When length of wire is doubled i.e. 2l
Also it's area of cross section becomes half i.e
2
A
Resistance R=
A
ρl
=20Ω
New Resistance ,
R
′
=
A
′
ρl
′
=
A
ρ(2l)×2
=4
A
ρl
=4(
A
ρl
)
=4×20
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