Question

V AABC ~ ADEF and their areas are
64cm, 121 cm if EF = 15.4 cm
then find Bc?​

Answer 1

It is given that:

∆ABC ~ ∆DEF

We know that the ratio of areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides.

ar(∆ABC)/ar(∆DEF)= (BC)2/(EF)2

64/121= (BC/EF)2

(8/11)2= (BC/15.4)2

8/11= BC/15.4

BC= 15.4×8/11= 11.2cm

Hence, BC = 11.2 cm.

Answer 2

$\frac{ar(abc)}{ar(def)} = ( \frac{bc}{ef} ) ^{2}$

$\frac{64}{121} = ( \frac{bc}{15.4} ) ^{2}$

$\frac{8}{11} = \frac{bc}{15.4}$

$= > bc$

$= \frac{8 \times 15.4}{11}$

$= 11.5 \: cm$

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