Question

v) An object oscillates 360 times in 9 seconds what will be its time period and frequency? Same heft​

Answer 1

Explanation:

Time period =

Number of oscillations in time t

t

=

40

4

=0.1 s

Frequency =

Time period

1

=10 Hz

refer to this n solve

Answer 2

Given:-

• An object oscillates 360 times in 9 seconds

To find:-

• Time Period and frequency.

Solution:-

• Time period= Time taken/number of oscillations
• Time period = 9/360
• = 0.025 s
• Frequency = Number of oscillations/ Time Taken
• Frequency = 360/9
• =40

Hence , Time period = 0.0025s and Frequency =40Hz