Question

V and I are given by the following equation in an A.C. circuit :
V = 100 sin(100t) V, I = 100 sin(100t+ π/3] mA. The power in the circuit is equal to.......... W.choose the correct option from the given options.
(A) 104
(B) 10
(C) 2.5
(C) 5.0

Answer 1

In an ac circuit V = 100 sin(100t) volt and I = 100 sin (100t + 600) mA. I = 100 sin (100t + 600) mA.

The power dissipated in the circuit is. 104 W. 10 W. 2.5 W.

Circuit Variables P 1.7 C/m3 = 1.6022× 10−19 × 1029 = 1.6022× 1010 C/m3 C/M.

Now we just substitute the values for v and i into the equation for power.

20e−1 sin 3 = 1.04 A p(20 ms) = vi = 5.39W [b] p = vi = 2000e−100t sin.2 150t.