V) Answer the following: 1. Carefully read the experiments given below. Identify the type of reaction taking place in each experiment and write the difference between each of them. Also, write a balanced chemical equation each type of reaction. a. Experiment-1: A piece of magnesium ribbon was burnt on a flame. As a result, white powder or ash is formed. b. Experiment-2: When an iron nail was dipped in the copper sulphate solution, the blue copper sulphate solution turned green and a brown deposit formed on the iron nail. c. Experiment-3: A solution of sodium chloride was dissolved in silver nitrate solution. As a result, white cloudy compound was formed. d. Experiment-4: Whereas when, sulphuric acid was mixed with sodium hydroxide solution, water and sodium sulphate salt were formed.
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Answer:
2Mg+ O2→ 2MgO
combination reaction .
Fe +CuSo4 → Feso4 + cu
double displacement reaction
NaCl + AgNo3 → AgCl + NaNo3
double displacement reaction
H2SO4 + 2NaOH → 2H2O + Na2SO4
neutralization reaction
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