(v) ax^2 - 13x + b = 0; x = 3/2and x =2/3 , find a, b,
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Answer:
Step-by-step explanation:
P(X)=AX^3-13X+B
P(3/2)=A*(3/2)^2 -13*3/2+B
= 9/4A-39/2+B
9/4A-39/2+B=0
B=39/2-9/4A
P(X)= AX^2-13X+B
P(2/3) = A*(2/3)^2 -13*2/3+B
=4/3A-26/3+39/2-9/4A
4/3A-26/3+39/2-9/4A=0
4/3A -9/4A=-39/2+26/3
-11/12A=-65/6
-11A=-65/6*12
-11A=-130
A=-130/-11= 11.81
B= 39/2-9/4*11.81
= 78-106.29/4
=28.29/4
=7.0725
A=11.81
B=7.0725
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