Question

(v) Construct a galvanic cell from the electrodes
CO3+ Co and Mn2+ | Mn Ec=
=182 V, E= -113 V.
Calculate E​

Answer 1

Answer:

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Explanation:

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Answer 2

Given:

Cell potential of Co=182V

Cell potential of Mn = -113V

To find:

Cell potential and cell representation.

Solution:

formula used for finding cell potential,

cell potential of cell = cell potential of cathode - cell potential of anode

electrode reactions are:

at anode: 3×( Mn(s) → Mn²⁺(aq) + 2e⁻ )

at cathode: 2×( Co³⁺(aq) + 3e⁻ → Co(s) )

anode representation is Mn(s)IMn²⁺(aq)

and cathode representation is Co³⁺(aq)|Co(s)

so, the overall galvanic cell representation is,

    Mn(s)|Mn²⁺(aq)║Co³⁺(aq)|Co(s)

therefore, electrode potential will be calculated as-

  E = E at cathode - E at anode

  E = E of Mn²⁺|Mn - E at Co³⁺|Co

  E = 182V - (- 113V)

  E = 295V