(v) cotx-cot2x = 2 what is the general solutions of x
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Prove that ,
Cot X - Cot 2X = 2
Answer - Cos X /SinX - Cos 2X /Sin2X =2
Or , Sin2X . Cos X - SinX . Cos 2x /Sinx . Sin2X = 2
Or, Sin(2X -X) = 2Sin2X . SinX
Or ,SinX - 2Sin2X . SinX = 0
Or, SinX (1 - 2Sin2X) = 0
Either ,
Sin X = 0
X = n pie (Based on formula )
Or, 1 - 2Sin2X =0
2Sin2X = 1
Sin2X = 1/2
Sin2X = Sin pi / 6
( as we know 1/2 = Sin 30 degree = pi /6 )
2X = n. pi + ( -1 ) ^n .pi / 6
Therefore , X = n. Pi /2 + (-1)^n . Pi /12
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