(v) Determine the nature of the roots for the quadratic equation :
√3x² + √2x - 2√3 = 0.
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Real and distinct roots
Step-by-step explanation:
√3x²+√2x-2√3 = 0
To determine the nature of the roots, we need to find the value of the Discriminant, b²-4ac
If discriminant = 0, the roots are equal
discriminant > 0, the roots are real and distinct
discriminant < 0, no real roots exist
Let's find the discriminant for the given equation
here a = √3, b =√2 and c = 2√3
b²-4ac = (√2)² - 4×√3×-2√3
= 2 + 24 = 26
Hence the equation has real and distinct roots.
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