Question

(V)
Find the least number whi
so as to get a perfect sq
obtained
(i) 402
(ü
(v) 4000
.​

Answer 1

Step-by-step explanation:

Given Find the least number which  must be subtracted from each of the given numbers so as to get a perfect sq . Also find square root of the perfect square obtained

(i) 402

2. 4000

• First we need to find the square root of 402 by long division method.
• So we have            2  0
•                     -----------------------------------
•                           2  4  0 2
•                           2   4
•                ---------------------------------------
•                        40  0  0 2
•                               0  0 0
•                ----------------------------------------------
•                                       2
•  So the remainder is 2 since remainder is not 0, 402 is not a perfect square..
• Now we need to find the least number that has to be subtracted to make it a perfect square.
• So subtracting the remainder 2 from 402 that is 402 – 2 = 400.
• Therefore 400 is a perfect square.
•      20 x 20 = 400
• 4000
• Now we need to find the square root of 4000 we get
•                                    6   3
•             ------------------------------------------
•                               6   4000
•                               6   36
•                -----------------------------------
•                            123     400
•                                       369
•              ------------------------------------------
•                                         31
• So So the remainder is 31 since remainder is not 0, 4000 is not a perfect square..
• Now we need to find the least number that has to be subtracted to make it a perfect square
• So subtracting the remainder 31 from 4000 that is 4000 – 31 = 3969.
• Therefore 3969 is a perfect square.
• 63 x 63 = 3969

Reference link will be

https://brainly.in/question/16643057