Question

(v) Find the value of the discriminant (A) for the quadratic equation x2 - 6x – 5 =0.
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Answer 1

Answer:

X²-6x-5=0

Step-by-step explanation:

Comparing X²-6x-5=0 with ax²+bx+c=0

a=1, b=-6, c=-5,

Therefore b²-4ac=(-6)²-4×1×-5

=36+20

b²-4ac=56

This is right answer friends

Answer 2

Answer:

The value of the discriminant will be 56.

Step-by-step explanation:

Given: The quadratic equation is$x^2 - 6x - 5 =0$.

We have to find the value of the discriminant.

The formula is used to calculate the discriminant is:$D=b^2-4ac$

We are solving in the following way:

We have,

The quadratic equation is$x^2 - 6x - 5 =0$.

Here, a=1, b=-6 and c=-5

So, the value of the discriminant is will be:

$D=b^2-4ac$

$D=(-6)^2-4\times1\times(-5)\\D=36+20\\D=56$

Hence, the value of the discriminant will be 56.