Question

(v) Find the value of x in each triangle.​

Answer 1

Step-by-step explanation:

(a) In first triangle

the line of length 64 is dividing the base and the line joined to it from the left in half.

Let the base be 2z and the other line be 2y.

We know that 4x is twice if 64 because the triangle formed from the sides y, z and 64 is half of the triangle 2y, 2z and 4x.

So,

4x = 2*64 = 128

x = 128/4 = 31

x = 31

(b) Now, let the left side be 2y and the right side be 2z

Here x - 8 is half of 40 because the side x - 8 is dividing 2y and 2z into half that is y and z so x - 8*2 = 40

2x - 16 = 40

2x = 56

x = 56/2

x = 28

(c) Now, let the base be 2y and right side be 2z.

Here, the side x+8 is dividing the lines 2y and 2z into half that is into y and z, so 6x is twice of x+8.

6x = 2x+16

6x - 2x = 16

4x = 16

x = 16/4

x = 4