V=(gh)1/2 dimensionally correctness of this equation
Answers
Answered by
0
Answer:
[v] = [LT-1] -----(1)
[g] = [LT-2]-----(2)
[h]= [L]--------(3)
from 1 and 3. [gh]= [LT-2][L] = [L2T-2]
not equal to [v]
if it is useful mark it as brainliest answer and follow me for best answers
Similar questions