Question

v)How many kilocalories of heat is needed to heat 300 ml of water from 20degree Celcius to 40 degree celcius?The specific heat of water is 1cal/g degree celcius.​

Answer 1

Answer:

Given :

Mass =5kg

T1=20∘C,T2=100∘C

ΔT=100−20=80∘C

Q=m×C×ΔT

where C= specific heat capacity of water 

=4200J/(kgK)

Q=5×4200×80

=1680000 Joule.

=1680KJ

Explanation:

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