Math, asked by nutan0, 3 months ago

v) If log32 N
=-
then the value of N is equal to
5​

Answers

Answered by kalakarthikdurai20
0

Answer:

32N = X

32 × 5 = x

160 = x

thus, 32n = 160

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Answered by pulakmath007
0

The value of N = 1/8

Given :

\displaystyle \sf{  log_{32}(N)  =  -  \frac{3}{5}  }

To find :

The value of N

Solution :

Step 1 of 2 :

Write down the given equation

Here the given equation is

\displaystyle \sf{  log_{32}(N)  =  -  \frac{3}{5}  }

Step 2 of 2 :

Find the value of N

\displaystyle \sf{  log_{32}(N)  =  -  \frac{3}{5}  }

\displaystyle \sf{ \implies  N =  {(32)}^{ -  \frac{3}{5} } }

\displaystyle \sf{ \implies  N =  {( {2}^{5} )}^{ -  \frac{3}{5} } }

\displaystyle \sf{ \implies  N =  {( {2}^{} )}^{ -  \frac{3}{5} \times 5 } }

\displaystyle \sf{ \implies  N =  {( {2}^{} )}^{ -  3} }

\displaystyle \sf{ \implies  N =  \frac{1}{ {2}^{3} } }

\displaystyle \sf{ \implies  N =  \frac{1}{ 8 } }

Hence the required value of N = 1/8

Correct question : Find the value of N if \displaystyle \sf{  log_{32}(N)  =  -  \frac{3}{5}  }

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