Question

V) If the cost of bananas is increased by 2 per
dozen, one can get one dozen less bananas for
840. Find the original cost of one dozen
bananas.​

Answer 1

Step-by-step explanation:

let the original cost of bananas be x rs

dozen of banana be x rs

no

dozen of bananas =840=840/x

cost is increased by1 rs dozen

new cost of 1 dozen bananas =(x+1)

now no of dozen of for rs840=840/x+1

by given condition

840/x-840/x+1

1/x-1/x+1=2/840

1/x2-x=1/420

x2-x=420

x2+21x-20x-420=0

x=-21or x=20

cost cannot be negative

original cost of 1 dozen banana is random 20