Question

v) If the inner length, breadth and height of a cuboidal box are 10 cm, 8 cm and 5

cm respectively then the maximum number of cubes of sides 2 cm that can be

placed in the box is

(a) 400 (b) 200 (c) 50 (d) 40​

Answer 1

Answer:

50

Step-by-step explanation:

Given :

length of cuboid : 10 cm

breadth : 8 cm

height : 5 cm

therefore ,

volume of cuboid = l*b*h

= 10*5*8

= 400 cm^3

according to question

2 cm of edge of cube is cutted from cuboid

therefore

volume of cuboid = n* volume of cube

400 cm^3 = n* a^3

400 cm^3 = n* 8

n = 400/8

n = 50......