Question

v) If the system (2a-1)x-3y=5 and then 3x+(b-2)y=3 has infinity many solution a) 4a+b=0 b) 4a+b=2ab c) 4a+b=2ab+11 d) 4a+b=2ab-11

Answer 1

Answer:

The equations are

2x−3y−7=0

(a+b)x−(a+b−3)y−(4a+b)=0

Here, a1=2,b1=−3,c1=−7

a2=a+b,b2=−(a+b−3),c2=−(4a+b)

The system of linear equations has infinite solutions

∴a2a1=b2b1=c2c1

⇒a+b2=−(a+b−3)−3=−(4a+b)−7

⇒a+b2=(a+b−3)3

⇒

Step-by-step explanation:

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